What is rectangular hyperbola?
When the transverse axis of a hyperbola is equal to its conjugate axis then the hyperbola is called a rectangular or equilateral hyperbola.
The standard equation of the hyperbola x2a2 - y2b2 = 1 ………… (i)
The transverse axis of the hyperbola (i) is along x-axis and its length = 2a.
The conjugate axis of the hyperbola (i) is along y-axis and its length = 2b.
According to the definition of rectangular hyperbola we get, a = b
Therefore, substitute a = b in the standard equation of the hyperbola (i) we get,
x2a2 - y2b2 = 1
⇒ x2a2 - y2a2 = 1
⇒ x2 - y2 = a2, which is the equation of the rectangular hyperbola.
1. Show that the eccentricity of any rectangular hyperbola
is √2
Solution:
The eccentricity of the standard equation of the hyperbola x2a2 - y2b2 = 1 is b2 = a2(e2 - 1).
Again, according to the definition of rectangular hyperbola we get, a = b
Therefore, substitute a = b in the eccentricity of the standard equation of the hyperbola (i) we get,
a2 = a2(e2 - 1)
⇒ e2 - 1 = 1
⇒ e2 = 2
⇒ e = √2
Thus, the eccentricity of a rectangular hyperbola is √2.
2. Find the eccentricity, the co-ordinates of foci and the length of semi-latus rectum of the rectangular hyperbola x2 - y2 - 25 = 0.
Solution:
Given rectangular hyperbola x2 - y2 - 25 = 0
From the rectangular hyperbola x2 - y2 - 25 = 0 we get,
x2 - y2 = 25
⇒ x2 - y2 = 52
⇒ x252 - y252 = 1
The eccentricity of the hyperbola is
e = √1+b2a2
= √1+5252, [Since, a = 5 and b = 5]
= √2
The co-ordinates of its foci are (± ae, 0) = (± 5√2, 0).
The length of semi-latus rectum = b2a = 525 = 25/5 = 5.
3. What type of conic is represented by the equation x2 - y2 = 9? What is its eccentricity?
Solution:
The given equation of the conic x2 - y2 = 9
⇒ x2 - y2 = 32, which is the equation of the rectangular hyperbola.
A hyperbola whose transverse axis is equal to its conjugate axis is called a rectangular or equilateral hyperbola.
The eccentricity of a rectangular hyperbola is √2.
● The Hyperbola
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