Perimeter and Area of Regular Hexagon
Here we will discuss about the perimeter and area of a Regular hexagon and some example problems.
Perimeter (P) = 6 × side = 6a
Area (A) = 6 × (area of the equilateral ∆OPQ)
= 6 × √34 a2
= 3√32 a2
If the area of a regular hexagon is 24√3 cm2, find its perimeter.
Solution:
Let the side of a regular hexagon be a.
Then, its area = 3√32 × (Side)2
= 3√32 × a2
Therefore, 24√3 cm2 = 3√32 × a2
⟹ a2 = 48√33√3 cm2
⟹ a2 = 16
⟹ Therefore, a ⟹ 4 cm.
Therefore, perimeter = 6a = 6 × 4 cm = 24 cm.
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