In Worksheet on elimination of unknown angle(s) using Trigonometric identities we will prove various types of practice questions on Trigonometric identities.
Here you will get 11 different types of elimination of unknown angle using Trigonometric identities questions with some selected questions hints.
1. Eliminate θ (theta) in each of the following:
(i) x = a sec θ, y = b tan θ
(ii) a sin θ = p, b tan θ = q
(iii) sin θ + cos θ = m, tan θ + cot θ = n
(iv) sin θ – cos θ = m, sec θ - csc θ = b
2. If sin θ + cos θ = m and sec θ + csc θ = n, then prove that
n(m2 – 1) = 2m.
Hint: n = sec θ + csc θ
⟹ n = 1cosθ + 1sinθ
⟹ n = sinθ+cosθsinθcosθ
⟹ n = msinθcosθ
⟹ sin θ cos θ = mn ......... (i)
Now, m2 – 1 = (sin θ + cos θ)2 - 1
= (sin2 θ + sin2 θ + 2 sin θ cos θ) - 1
= 1 + 2 sin θ cos θ - 1
= 2 sin θ cos θ
= 2mn, From (i)
3. If l1 cos θ + m1 sin θ + n1 = 0 and l2 cos θ + m2 sin θ + n2 = 0 then prove that
(m1n2 – n1m2)2 + (n1l2 – n2l1)2 = (l1m2 – l2m1)2
4. If a sin2 ϕ + b cos2 ϕ = c and p sin2 ϕ + q cos2 ϕ = r then prove that
(b – c)(r – p) = (c – a)(q – r).
Hint: b−cc−a = b−(asin2ϕ+bcos2ϕ)(asin2ϕ+bcos2ϕ)−a
= (b−a)sin2ϕ(b−a)cos2ϕ
= tan2 ϕ.
Similarly, q−rr−p = q−(psin2ϕ+qcos2ϕ)(psin2ϕ+qcos2ϕ)−p
= (q−p)sin2ϕ(q−p)cos2ϕ
= tan2 ϕ.
Therefore, b−cc−a = q−rr−p.
5. If a sec θ + b tan θ + c = 0 and a’ sec θ + b’ tan θ + c’ = 0 then prove that
(bc’ – b’c)2 – (ca’ – ac’)2 = (ab’ – a’b)2.
6. If xacosθ = ybsinθ and axcosθ - bysinθ = a2 – b2, prove that
x2a2 + y2b2 = 1.
Hint: xcosθ ∙ b - ysinθ ∙ a + 0 = 0 and xcosθ ∙ a - ysinθ ∙ b - (a2 - b2) = 0.
By cross multiplication, xcosθa(a2−b2) = ysinθb(a2−b2) = 1(a2−b2)
⟹ xa = cos θ, yb = sin θ. Square these and add.
7. If tan A + sin A = m and tan A - sin A = n then prove that
m2 – n2 = 4 √mn.
8. If x sin3 A + y cos3 A = sin A ∙ cos A and x sin A – y cos A = 0 then prove that
x2 + y2 = 1.
Hint: x sin A - y cos A = 0
⟹ tan A = yx
Again, x ∙ sin2AcosA + y ∙ cos2AsinA = 1
⟹ x ∙ yx sin A + y ∙ xy cos A = 1
⟹ x cos A + y sin A = 1
Now, (x sin A - y cos A)2 + (x cos A + y sin A)2 = 02 + 12
9. If csc β – sin β = m3; sec β – cos β = n3 then prove that,
m2n2(m2 + n2) = 1.
10. If a = r cos θ cos β, b = r cos θ sin β and c = r sin θ then prove that,
a2 + b2 + c2 = r2.
11. If p = a sec A cos B, q = b sec A sin B and r = c tan A then prove that,
p2a2 + q2b2 - r2c2 = 1.
Answers
1. (i) x2a2 - y2b2 = 1.
(ii) a2p2 - b2q2 = 1.
(iii) n(m2 – 1) = 2
(iv) b(1 – a2) = 2a
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