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Trigonometrical Ratios of 0°

How to find the Trigonometrical Ratios of 0°?

Let a rotating line OX rotates about O in the anti clockwise sense and starting from its initial position OX traces out ∠XOY = θ where θ is very small.

Trigonometrical Ratios of 0°

Take a point P on OY  and draw ¯PQ perpendicular to OX  .

Now according to the definition of trigonometric ratio we get,
sin θ = ¯PQ¯OP;
cos θ = ¯OQ¯OP and
tan θ = ¯PQ¯OQ           

When θ is slowly decreases and finally tends to zero then,
(a) ¯PQ slowly decreases and finally tends to zero and

(b) the numerical difference between ¯OP  and ¯OQ  becomes very small and finally tends to zero.

Hence, in the Limit when θ → 00 then ¯PQ → 0 and ¯OP   → ¯OQ  . Therefore, we get
limθ0sinθ=limθ0¯PQ¯OP=0¯OQ [since, θ → 0° therefore, ¯PQ → 0].
= 0

Therefore sin 0° = 0

limθ0cosθ=limθ0¯OQ¯OP=¯OQ¯OQ, [since, θ → 0° therefore, ¯OP¯OQ].
= 1

Therefore cos 0° = 1

limθ0tanθ=limθ0¯PQ¯OQ=0¯OQ [since, θ → 0° therefore, ¯PQ → 0].
= 0

Therefore tan 0° = 0

Thus,
csc 0° = 1sin0°=10, [since, sin 0° = 0] 
= undefined

Therefore csc 0° = undefined


sec 0° = 1cos0°=11, [since, cos 0° = 1] 
= 1

Therefore sec 0° = 1


cot 0° = 1tan0°=10, [since, tan 0° = 0] 
= undefined

Therefore cot 0° = undefined

Trigonometrical Ratios of 0 degree are commonly called standard angles and the trigonometrical ratios of these angles are frequently used to solve particular angles.

 Trigonometric Functions







11 and 12 Grade Math

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