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Problems on Condition of Perpendicularity

Here we will solve various types of problems on condition of perpendicularity of two lines. 

1. Prove that the lines 5x + 4y = 9 and 4x – 5y – 1 = 0 are perpendicular to each other.

Solution:

Equation of the 1st line 5x + 4y = 9.

Now we need to express the above equation in the form y = mx + c.

5x + 4y = 9

4y = -5x + 9

y = -54x + 94

Therefore, the slope (m 1) of the 1st line = -5/4

Equation of the second line 4x - 5y - 1 = 0

Now we need to express the above equation in the form y = mx + c.

4x – 5y – 1 = 0

⟹ -5y = -4x + 1

⟹ y = 4515 

Therefore, the slope (m 2) of the 2nd line = 45

Now,

m 1 × m 2 = 54  ×  45= -1

Therefore, the given lines are perpendicular to each other.


2. Find the value of k if the lines 7y = kx + 4 and x + 2y = 3 are perpendicular.

Solution:

The slope of the lines can be found by comparing the equations with y = mx + c.

Equation of the first straight line 7y = kx + 4

Now we need to express the given equation in the form y = mx + c.

7y = kx + 4

⟹ y = k7x + 47

Therefore, the slope (m1) of the given line = k7

Equation of the second line x + 2y = 3

Now we need to express the given equation in the form y = mx + c.

x + 2y = 3

⟹ 2y = -x + 3

⟹ y = -12x + 32

Therefore, the slope (m2) of the given line = -12

Now according o the problem the two given lines are perpendicular.

i.e., m1 × m2 = -1

k7 × -12 = -1

⟹ -k14 = -1

⟹ k = 14

Therefore, the value of k = 14

 Equation of a Straight Line










10th Grade Math

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