When the coefficients of two straight lines are proportional they are called identical straight lines.
Let us assume, the straight lines a1 x + b1 y + c1 = 0 and a2 x + b2y + c2 = 0 are identical then
a1a2 = b1b2 = c1c2
To get the clear concept let us proof the above statement:
a1x + b1y + c1 = 0 .…………………..(i)
a2x + b2y + c2 = 0 .…………………..(ii)
Convert the straight line a1x + b1y + c1 = 0 in slope-intercept form we get,
y = a1b1x - c1b1
Similarly, convert the straight line a2x + b2y
+ c2 = 0 in slope-intercept form we get,
y = a2b2x - c2b2
If (i) and (ii) represent the equations of the same straight line then their slopes are equal.
i.e., - a1b1 = - a2b2
or, a1a2 = b1b2 .…………………..(iii)
Again, the y-intercepts of lines (i) and (ii) are also equal.
Therefore, - c1b1 = - c2b2
or, b1b2 = c1c2 .…………………..(iv)
Therefore, from (iii) and (iv) it is clear that (i) and (ii) will represent the same straight line when
a1a2 = b1b2 = c1c2.
● The Straight Line
11 and 12 Grade Math
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