We will learn how to form the equation of a circle when the centre of the circle coincides with the origin.
The equation of a circle with centre at (h, k) and radius equal to a, is (x - h)2 + (y - k)2 = a2.
When the centre of the circle coincides with the origin i.e., h = k = 0.
Then the equation (x - h)2 + (y - k)2 = a2 becomes x2 + y2 = a2
Solved examples on the central form of the equation of a circle whose centre coincides with the origin:
1. Find the equation of the circle whose centre coincides with the origin and radius is √5 units.
Solution:
The equation of the circle whose centre coincides with the origin and radius is √5 units is x2 + y2 = (√5)2
⇒ x2 + y2 = 5
⇒ x2 + y2 - 5 = 0.
2. Find the equation of the circle whose centre coincides with the origin and radius is 10 units.
Solution:
The equation of the circle whose centre coincides with the origin and radius is 10 units is x2 + y2 = (10)2
⇒ x2 + y2 = 100
⇒ x2 + y2 - 100 = 0.
3. Find the equation of the circle whose centre coincides with the origin and radius is 2√3 units.
Solution:
The equation of the circle whose centre coincides with the origin and radius is 2√3 units is x2 + y2 = (2√3)2
⇒ x2 + y2 = 12
⇒ x2 + y2 - 12 = 0.
4. Find the equation of the circle whose centre coincides with the origin and radius is 13 units.
Solution:
The equation of the circle whose centre coincides with the origin and radius is 13 units is x2 + y2 = (13)2
⇒ x2 + y2 = 169
⇒ x2 + y2 - 169 = 0
5. Find the equation of the circle whose centre coincides with the origin and radius is 1 unit.
Solution:
The equation of the circle whose centre coincides with the origin and radius is 1 unit is x2 + y2 = (1)2
⇒ x2 + y2 = 1
⇒ x2 + y2 - 1 = 0
● The Circle
11 and 12 Grade Math
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