Area of a Circular Ring

Here we will discuss about the area of a circular ring along with some example problems.

The area of a circular ring bounded by two concentric circle of radii R and r (R > r)

= area of the bigger circle – area of the smaller circle

= πR$^{2}$ - πr$^{2}$

= π(R$^{2}$ - r$^{2}$)

= π(R + r) (R - r)

Therefore, the area of a circular ring = π(R + r) (R - r), where R and r are the radii of the outer circle and the inner circle respectively.

Solved example problems on finding the area of a circular ring:

1. The outer diameter and the inner diameter of a circular path are 728 m and 700 m respectively. Find the breadth and the area of the circular path. (Use π = $\frac{22}{7}$).

Solution:

The outer radius of a circular path R = $\frac{728 m}{2}$ = 364 m.

The inner radius of a circular path r = $\frac{700 m}{2}$ = 350 m.

Therefore, breadth of the circular path = R - r = 364 m - 350 m = 14 m.

Area of the circular path = π(R + r)(R - r)

                                    = $\frac{22}{7}$(364 + 350) (364 - 350) m$^{2}$

                                    = $\frac{22}{7}$ × 714 × 14 m$^{2}$

                                    = 22 × 714 × 2 m$^{2}$

                                    = 31,416 m$^{2}$

Therefore, the area of the circular path = 31416 m$^{2}$

2. The inner diameter and the outer diameter of a circular path are 630 m and 658 m respectively. Find the area of the circular path. (Use π = $\frac{22}{7}$).

Solution:

The inner radius of a circular path r = $\frac{630 m}{2}$ = 315 m.

The outer radius of a circular path R = $\frac{658 m}{2}$ = 329 m.

Area of the circular path = π(R + r)(R - r)

                                    = $\frac{22}{7}$ (329 + 315)(329 - 315) m$^{2}$

                                    = $\frac{22}{7}$ × 644 × 14 m$^{2}$

                                    = 22 × 644 × 2 m$^{2}$

                                    = 28,336 m$^{2}$

Therefore, the area of the circular path = 28,336 m$^{2}$

9th Grade Math

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