Here we will prove that in an isosceles triangle, the angles opposite to the equal sides are equal.
Solution:
Given: In the isosceles ∆XYZ, XY = XZ.
To prove ∠XYZ = ∠XZY.
Construction: Draw a line XM such that it bisects ∠YXZ and meets the side YZ at M.
Proof:
Statement 1. In ∆XYM and ∆XZM, (i) XY = XZ (ii) XM = XM (iii) ∠YXM = ∠ZXM 2. ∆XYM ≅ ∆XZM 3. ∠XYZ = ∠XZY. (Proved) |
Reason 1. (i) Given. (ii) Common side. (iii) XM bisects ∠YXZ. 2. By SAS criterion. 3. CPCTC. |
From Angles Opposite to Equal Sides of an Isosceles Triangle are Equal to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.
Nov 23, 24 03:45 PM
Nov 23, 24 03:14 PM
Nov 23, 24 02:51 PM
Nov 23, 24 12:22 AM
Nov 22, 24 12:34 AM
New! Comments
Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.